All cards from Ace to 5 (1, 2, 3, 4 and 5) are removed from the deck and 2 cards are chosen from the remaining cards, find the probability that both are face cards.

- 33/248
- 35/248
- 47/248
- 42/248
- None of these

Option 1 : 33/248

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**Concept:-**

1. Classical concept of probability.

2. Deck of cards has 12 face cards (3 each from 4 suits)

**Formula:-**

nC2 for choosing 2 from n items.

**Calculation:-**

Number of cards after removal = 52 – 5 × 4(1 – 5 from all 4 suites) = 32

Probability of choosing two face cards = 12C2/32C2 = 33/248

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